Answer: there are different ways to solve:

Sol 1 :- (0! + 0! + 0! + 0! + 0!)! = 120

Here '!' symbol is used for factorial.

And 0! = 1

= (0! + 0! + 0! + 0! + 0!)!

= (1 + 1 + 1 + 1 + 1)!

= 5!

= 120

Sol 2 :- (cos (0) + cos (0) + cos (0) + cos (0) + cos (0))! = 120

= (cos (0) + cos (0) + cos (0) + cos (0) + cos (0))!

= (1 + 1 + 1 + 1 + 1)!

= 5!

= 120

Similarly you can replace cos (0) with tan (0).

Sol 3 :- (0!0! * 0!0!) - 0! = 120

= (0!0! * 0!0!) - 0!

= (11 * 11) - 1

= 121 - 1

= 120