One is being added at unit place, so let x be a number 10x+1 = 3(x+10^5) therefore x = 42857
Solution:
The 5 digit number is: 42857
The number with a one after it is 10x + 1. With a 1 before it, it is 100,000 + x. Then 10x +1 = 3(100,000 + x), and x = 42,857. Therefor the 5 digit number is: 42857
1, 2, 3, 4, 5, 6, 7, 8, 9, 10 The above are the first 10 positive integers. The product of the numbers before the number __ is the same as the product of the numbers after that number.
The sum of all digits of a 5 digit number is equal to the number of two digit formed by using the ten thousands and hundreds place digit in order. If five digit number has 1, 2 , 3 & 4 and no digit is repeated in the number, then What are the total number of possible number?
