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28 x 23 = 644 , so B = 2.
=>10B^2+11B-62=0, A quadratic equation,=> two solutions, one real=>B=2, Another imaginary.
In the equation below A, B & C represent different digits.
Can you find their value from the given information?
√a + b = 7
√b + a = 11
Provide your working also?
If a and b are real numbers that satisfy the equation below, what is the value of a and b respectively?
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