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Our related question with answer
A bag has 100 balls out of which there is one green ball. 50 balls are randomly selected. What is probability that the green ball is selected.
P = 99c49/100C50 = 1/2
Explanation P = success cases/all cases All cases = 100C50 Success cases = 1 green ball and any remaining any 49 ball i.e. 99C49
So P=99c49/100C50 = (99!/(49!*50!))/(100!/(50!*50!)) = 1/49!/100/50! = 50/100 = 1/2
A bag contains 5 white, 4 red and 3 black balls. A ball is drawn at random from the bag, what is the probability that it is not black?
A bag contain 5 red balls and some blue balls. If the probability of drawing a blue ball from the bag is four time that of a red ball, then find the number of blue balls in the bag.
3 red, 2 white and 3 green balls are available in a bag. 2 balls are drawn one by one from the bag.
What will be the probability of one ball is white & other is green?
