The sum of the ages of A and B is 63 years. After 6 years, the age of B will be four times that of the A. What is the age of B ?
A + B = 63
A + 6 + B + 6 = 63 + 12 ---- 1
But B+6 = 4(A + 6)
ie., 1 becomes
A + 6 + 4(A + 6) = 75
A = (75/5) - 6 = 9.
B = 63 - A
B = 63 - 9
B = 54.
The age difference between two brothers is 6 years.
After 6 years the ratio between the age is 8 : 5.
What would be the sum of their present ages?
Mohan's ages is 1/6 th of his father's age. The father's age will be twice of Suresh's ages, after 10 years. If Suresh's eight birhtday was celebrated 2 years before, what is Mohan's present age?
Sum of the ages of a boy and his father is 49 years. Before 11 years Father's age was 8 times the age of the boy. What was the age of father (in years) at the time of birth of the child?
The sum of the present ages of a father and his son is 60 years. Six year ago, father's age was five times the age of the son. After 6 years, what will be son's age?