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Answer: x*y = 5 as x=5 and y = 1
3^(x-y) = 81 = 3^4 or (-3)^4
in either case
x-y = 4 -- (i)
3^(x+y) = 729 = 3^6 or (-3)^6
in either case
x+y = 6 - (ii)
Solving (i) and (ii)
x =5 and y =1
x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be
x and y are distinct 2 digit numbers such that y is obtained by reversing the digits of x.
Suppose they also satisfy x^2 - y^2 = m^2 for some positive integer m, then find the value of x+y+m?
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