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Which is the smallest number of five digits which is divisible by 15, 27 and 35?

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Which is the smallest number of five digits which is divisible by 15, 27 and 35?
posted Mar 28, 2017 by anonymous

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1 Answer

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15×27×35 = (3×5)×(3×3×3)×(5×7)

It seems that the smallest subset needed could be:

3×3×3×5×7 = 945

and to get the first 5-digit number having this set of divisors:

945 × 11 = 10 395

answer Mar 28, 2017 by anonymous



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