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3 Answers

0 votes

15 DEGREES height of the equilateral triangle is 0.866 times the base. let the base be unity so the height is 0.866 leaving the perpendicular distance from P to AB as 1-.866=0.134 so that alpha is tan inv(0.134/0.5) or 15 degrees.

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0 votes

Alpha is equal to 15 degree
Suppose let the side of equilateral triangle be x and this square has also side lengths equal to x . �DPA is isosceles as DP=DA =x. Now
In triangle DPA
2(90-alpha) + 30 = 180
Therefore solving we get
Alpha equals to 15

OR 2*(90-ALPHA)=150 OR

90-ALPHA=150/2=75

ALPHA=90-75=15