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A boy has Rs 728 in denomination of Rs 2, Rs 5 and Rs 10 notes in ratio of 3:2:4. What is the total num of notes he has?

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A boy has Rs 728 in denomination of Rs 2, Rs 5 and Rs 10 notes in ratio of 3:2:4 respectively. What is the total number of notes he has?

posted Dec 27, 2016 by anonymous

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3 Answers

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let notes of Rs 2 denomination be3 x. Their value is 6x. The notes of Rs. 5 denomination will be 2x whose value is 2x*5=10x. Similarly the notes of Rs 10 denomination counting 4x will have value 40x. Total value of 6x+10x+40x=728 which gives x=13. Check
2*39+5*26+10*52=78+130+520=728

answer Dec 28, 2016 by Kewal Panesar
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Total 13×9=117

answer Dec 28, 2016 by Subhash Gupta
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A: No of Rs 2
B: No of Rs 5
C: No of Rs 10
2 A + 5 B + 10 C = 728
A/3 = B/2 = C/4
Substituting B and C we will have:
2 A + 5 x 2/3 A + 10 x 4/3 A = 728
Therefor:
A = 39
B = 26
C = 52
39 x 2 + 26 x 5 + 52 x 10 = 728

answer Dec 28, 2016 by Ahmad Cheragh



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