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If altitude of a circular cylinder is increased 12 times and the base area is decreased to one ninth...

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The altitude of a circular cylinder is increased 12 times and the base area is decreased to one ninth of its value.
How much would be the change in surface area of new cylinder?

posted Nov 11, 2016 by anonymous

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3 Answers

+1 vote

let the original height = h and base radius = R.
let the new height = 12h and new radius = r.
now pi*r^2 = pi*R^2/9 ,r/R => 1/3 i.e R = 3r.
Original lateral surface area/ New lateral surface area = 2*pi*3r*h/ 2*pi*r*12h.
new lateral surface area = 4 original lateral surface area

answer Nov 11, 2016 by Viswambher Kambhampati
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In a circular cylinder , we have top area, lateral area and base area
Let us calculate the total surface of the cylinder, as follows:
top area = A, base area = A and lateral area = 2 x Pi x r x h = 2 x pi x sqroot ( A/Pi) x h
For the new coditions, top a = 1/9 A , base a = 1/9 A and
lateral area = 2 x pi x r x 12h = 2 x pi x sqroot ( 1/9 pi ) x 12 h = 8 x pi x sqrrot (A/pi) x h
Therefore,
top and base areas are decreased to 1/9 of the original value
the lateral surface is increased 4 (four times)

answer Nov 12, 2016 by anonymous
0 votes

6*pi*r*l-16*pi*r*r/9 The original surface area being 2*pi*r*l+2*pi*r*r and the new being 2*pi*(r/3)*12*l +2*pi*(r/3)^2

answer Dec 6, 2016 by Kewal Panesar



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