Solve the following equations -

a1+a2=8 b1-b2=6 a1+b1=13 a2+b2=8

a1 = 3.5, b1 = 9.5, a2 =4.5 and b2 = 3.5

a1 + a2 = 8 and a2 + b2 = 8. So a1 + a2 = a2 + b2 which gives a1 = b2. Now take b1 - b2 = 6 and using a1 = b2 we get b1 - a1 = 6. we have a1 + b1 = 13, So adding these two equations we get 2b1 = 19, So b1 = 9.5 It is easy to get remaining values from the remaining equations.

Let a1 and a2 be the roots or the equation (x- a)(x - b) = c and c != 0, then what are the roots of the equation (x - a1)(x - a2) + c = 0?

If 1,4,3=13; 4,5,4=9; 5,6,5=11 and 7,7,6=7 then 9,8,7=?

Can you solve the equations and find the value of the missing number?

In the picture you will see a football, basketball and a volley ball represent certain numbers.