if 3+4=21 , 5+6=55 , 2+7=18 then how much is 6+8=?

Thanks for the query.

The answer should be 84.

The equations are in the format of Sum of the two numbers * the first number. So, 3 +4 => Sum of the numbers * the first number = 7*3 = 21 Similarly the others.

Therefore, 6 + 8 => 14*6 = 84

6+8=14 14*6=84 so 84 is the answer.

14x6=84 `6+8=14

Answer is 84 The logic behind is: sum of 2 numbers(first no. and second no.) * first number = result 3+4=21 =>> (3+4) * 3 = 7 * 3 = 21 5+6=55 =>> (5+6) * 5 = 11 * 5 = 55 2+7=18 =>> (2+7) * 2 = 9 * 2 = 18 6+8=84 =>> (6+8) * 6 = 14 * 6 = 84

3*(3+4)=21 5*(5+6)=55 2*(2+7)=18 6*(6+8)=84

if 3+4=21 that is 3+4=7 and 7*3=21 6+8=86

84 6+8=14; 14*6=84 6+8=84

(3+4)*3=21 (5+6)*5=55 (2+7)*2=18 (6+8)*6=84 ANS: 84