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Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's..........

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Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?

posted Jun 29, 2016 by Rahul Chandel

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2 Answers

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After further 8 years the father would be 2.2 times the sons age.

F = 3*S
(F+8) = 2.5 (S+8)
F + 8 = 2.5 S + 20

replacing F with 3*S we get

3 S + 8 = 2.5 S +20
Solving this we get S = 24 (present age of Son)
therefore present age of Father is 72
The ratio (72+16) / (24+16) is 88 / 40 = 2.2

answer Jun 29, 2016 by Anup Desai
0 votes

Rotin is currently 24 and his father is 72. In 16 years, the father will be 88 and the son will be 40. The father would be 2.2 times older, he would probably die before reaching 88.

answer Jun 29, 2016 by anonymous



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