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Dual connectivity: split bearer related
Three semicircles (with equal radii) are drawn inside the large semicircle so that their diameters all sit on the diameter of the large semicircle. What is the ratio of the red area to the blue area?
Let the diameter of larger circle is r, so now radius of one small circle is r/6
total are of smaller circle: PIE*r^2/12
total are of larger circle: PIE*r^2/4
IM DISAPPOINTED YOURE TRYING TO CHEAT...
Anyway, answer is 1:3
Area of small semicircle A1=Pi.r^2/2
Area of big semicircle B1=9.Pi.r^2/2
Red area A=3.Pi.r^2/2
Blue area B=B1-A=9.Pi.r^2/2 - 3.Pi.r^2/2 = 3.Pi.r^2
Ratio A/B= 1/2
What is the ratio of area colored as red and area colored as blue?
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