Following figures shows a unit square ABCD. If the area of the octagon (in blue) can be expressed as 1/a find a?
In similar triangles W.BC and HXC WB is half of BC therefore HX is half of WB i.e. 0.5*0.5=0.25 units. Thus HV=0.25 also. The vertex angle of HVI is 350/8 = 45. Solution of the isosceles triangle HVI gives its height as 0.23097 and half of base as 0.095671. Thus area of one triangle is 0.23097*0.095671=0.022097. Thus area of the regular octagon =8* 0.022097=0.176777 units. The inverse of this is 5.656854. This corroborates solution over internet.
If ABCD is a square of area 1. E, F are mid points of AB and BC respectively. What is the area of blue region?
What is the area of the blue square divided by the area of square ABCD?
The given figure shows a circle, centred at O, enclosed in a square. Find the total area of shaded parts?
The given figure shows a triangle and a circle enclosed in a square. Find the area of the shaded parts?
In the figure, if ABCD and EFGC are squares with areas R and S respectively. What is the area of the blue region?