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What number, when multiplied by itself, has the same answer when it is added to itself?

–2 votes
1,610 views
What number, when multiplied by itself, has the same answer when it is added to itself?
posted Mar 3, 2016 by Prithvi

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7 Answers

+1 vote

2*2=4
2+2=4
So 2 must be an answer.
but
0*0=0
0+0=0
So 0 also be one of the answer.

answer Mar 3, 2016 by Double S
+1 vote

THE SOLUTIONS ARE;
1) 2+2=4
2*2=4
2)0+0=0
0*0=0
3) IT CONSIST OF AN IMAGINARY PART. SINCE IT IS NOT MENTIONED ABOUT REAL OR IMAGINARY NUMBER

2(i)^(4n) + 2(I)^(4n)=4(I)^(4n)=4
2(I)^(4n)*2(I)^(4n)=4(I)^(8n)=4
THE ANSWERS ARE 2,0,2(i)^(4n)

answer Mar 4, 2016 by Nithi Mani
0 votes

2 x 2 = 4
2 + 2 = 4

answer Mar 3, 2016 by 이기가
0 votes

Supposed that, the number is n.
According to the condition,
n*n = n+n
⇒ n² = 2n
⇒ n²-2n = 0
⇒ n(n-2) = 0
So, n=0
Or, n-2 = 0 ⇒n=2

answer Feb 18, 2018 by Yasin Hossain Siinan
–1 vote

Ans 2
2+2 = 4
2*2 = 4

answer Mar 3, 2016 by Muthulakshmi K
–1 vote

2*2=4
2+2=4
hence ans is 2

answer Mar 3, 2016 by Kirti Shukla
–1 vote

let no=a
then aa =a+a
a*2 =2a
solving,a=2 answer

answer May 9, 2016 by Gangadharan Kv



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