A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively.
What is the speed of the train?
Let's length of the train =x meters
Speed of the train =y m/sec
Then x/y=8 => x=8y
let the length of the train be x metres and its speed by y m/sec.
Then, x/y = 8 => x = 8y
Now, x + 264 /20= y
=> 8y + 264 = 20y
=> y = 22.
So Speed in m/sec= 22 m/sec
and Speed in km/hr=22x(18/5) =>79.2km/hr
let train speed= a m/s
and length of the train is x m
put the value of x in second
A 150 meters long train takes 10 seconds to cross Atul walking at 5 kmph in a direction opposite to that of the train.
Find the speed of the train.
How many seconds will a 468 m long train take to cross a man driving his motor bike at a speed of 39 km/hr in a direction of the moving train if the speed of the train is 120 km/hr?
A train travelling at a speed of 76 mph enters a tunnel 9/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?