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A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only.
Then, C alone can do the job in how many days ?
C alone can do the job in 48/5 = 9.6 days!
Let's say C can do the work alone in X days then;
1 day of work combined = 1/16+1/12+1/X = 1/4
by solving, we get 3X+4X+48 = 12X >> 5X=48 >> X=48/5 = 9.6 days.
A lays 1/16 distance per day; B lays 1/12 distance per day. With C, they lay 1/4 distance per day. So:
1/16 +1/12 + 1/C=1/4
C=48/5 days that it would take for C to do the job alone
X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?
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