A cube whose edge measures 8 cm is cut into cubes whose edge measures 1 cm.
Find the ratio of the surface area of the original cube to the sum of the surface areas of the new cube ?
Let a1=edge of whole cube=8cm
a2=edge of cut cube=1cm
No of cubes=N=V1 /V2=512/1=512nos
A1=Surface area of whole cube
A2=Total surface area of cut cubes
Ans is 1:8
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