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The answer is -1/2.
Tan A=Sin A/Cos A
Tan B=Sin B/Cos B
Tan A*Tan B= SinASinB/CosACosB=3
=CosACosB - 3CosACosB
Cos(A-B)=CosACosB + SinASinB
=CosACosB + 3CosACosB
Cos(A+B)/Cos(A-B) = -2CosACosB/4CosACosB
What would be the value of Sin(50 + A) - Cos(40 - A), share your working also?
If in a triangle ABC:
Cos A + Cos B + Cos C = 3/2
then what is so special about this triangle?
Try to solve this problem using substitution of only basic values of trigonometric functions(30,60,90) and post the complete solution?
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