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How much did Morrison receive for each ring?

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Professor Morrison sold a total of three precious rings on the black market for $1,750. Holmes was able to trace all three rings and found that Morrison had sold off the second ring for $50 more than the first one, and the third ring for $600 less than the second one.
How much did Morrison receive for each ring?

posted Nov 5, 2015 by Nikita Sehgal

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1 Answer

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Given:
Total sell price =$1750=S
second ring sold $50 more than first ring=first ring sold $50 less than second ring ....(i)
third ring sold $600 less than second ring................................................................................(ii)

Let's sell price of 2nd ring=S2
sell price of 1st ring=S1=(S2-$50)...............................from (i)
sell price of 3rd ring=S3=(S2-$600)............................from(ii)

S1+S2+S3=S
(S2-50)+S2+(S2-600)=1750
simplify formula
we get S2=800
S1=800-50=750
S3=800-600=200

S1+S2+S3=750+800+200
=1750
=S.........................hence proved.

so ans is Morrison received for
1st ring=$750
2nd ring =$800
3rd ring=$200

answer Nov 5, 2015 by Jaikumar Bhatia



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